Paired sample t test
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Example of paired sample t&-test (t&-test for related data)
It is believed that airfares between London and Budapest have fallen between 1997 and 1998. Travel agencies were sampled at random and their cheapest return air fare between these two celebrated cities was noted for the first week of January 1997 and 1998. The results were&: [Table goes here &- download the original to see it.] By means of a paired&-sample t&-test at the 5% significance level determine whether the belief that airfares have fallen is valid. Solution Firstly, find the differences between the pairs of values; find the squares of these differences and sum accordingly, as follows [Table goes here &- download the original to see it.] Then substitute into the formula [Equation goes here &- download the original to see it.] This gives the test value for the sample data. We must compare it with a critical value drawn from a table of such values. We are told to test the hypothesis at the 5% level, so that determines which column (or row) to use. The other row (or column) is for the degrees of freedom. In this test the degrees of freedom is one less than the number in the sample. Hence, the number of degrees of freedom is 5, since the number of pairs in the sample is 6. From tables, [Equation goes here &- download the original to see it.] Then [Equation goes here &- download the original to see it.]
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Contents of
Paired sample t test
1 Paired sample t&-test (t&-test for related data)
2 One&-step formula for paired sample t&-test (t&-test for related data)
3 Example of paired sample t&-test (t&-test for related data)
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